Exercise: Build a function that returns the sigmoid of a real number x. Use math.exp(x) for the exponential function.
# GRADED FUNCTION: basic_sigmoid
import math
defbasic_sigmoid(x): """ Compute sigmoid of x. Arguments: x -- A scalar Return: s -- sigmoid(x) """
### START CODE HERE ### (≈ 1 line of code) s = 1 / (1 + math.exp(-x)) ### END CODE HERE ###
return s
basic_sigmoid(3)
Exercise: Implement the sigmoid function using numpy.
# GRADED FUNCTION: sigmoid
import numpy as np # this means you can access numpy functions by writing np.function() instead of numpy.function()
defsigmoid(x): """ Compute the sigmoid of x Arguments: x -- A scalar or numpy array of any size Return: s -- sigmoid(x) """
### START CODE HERE ### (≈ 1 line of code) s = 1 / (1 + np.exp(-x)) ### END CODE HERE ###
return s
x = np.array([1, 2, 3]) sigmoid(x)
1.2 - Sigmoid gradient
Exercise: Implement the function sigmoid_grad() to compute the gradient of the sigmoid function with respect to its input x. The formula is: \[sigmoid\_derivative(x) = \sigma’(x) = \sigma(x) (1 - \sigma(x))\]
# GRADED FUNCTION: sigmoid_derivative
defsigmoid_derivative(x): """ Compute the gradient (also called the slope or derivative) of the sigmoid function with respect to its input x. You can store the output of the sigmoid function into variables and then use it to calculate the gradient. Arguments: x -- A scalar or numpy array Return: ds -- Your computed gradient. """
### START CODE HERE ### (≈ 2 lines of code) s = sigmoid(x) ds = s * (1 - s) ### END CODE HERE ###
Exercise: Implement image2vector() that takes an input of shape (length, height, 3) and returns a vector of shape (length*height*3, 1).
# GRADED FUNCTION: image2vector defimage2vector(image): """ Argument: image -- a numpy array of shape (length, height, depth) Returns: v -- a vector of shape (length*height*depth, 1) """
### START CODE HERE ### (≈ 1 line of code) v = image.reshape(image.shape[0]*image.shape[1]*image.shape[2], 1) ### END CODE HERE ###
return v
# This is a 3 by 3 by 2 array, typically images will be (num_px_x, num_px_y,3) where 3 represents the RGB values image = np.array([[[ 0.67826139, 0.29380381], [ 0.90714982, 0.52835647], [ 0.4215251 , 0.45017551]],
Exercise: Implement normalizeRows() to normalize the rows of a matrix. After applying this function to an input matrix x, each row of x should be a vector of unit length (meaning length 1).
# GRADED FUNCTION: normalizeRows
defnormalizeRows(x): """ Implement a function that normalizes each row of the matrix x (to have unit length). Argument: x -- A numpy matrix of shape (n, m) Returns: x -- The normalized (by row) numpy matrix. You are allowed to modify x. """
### START CODE HERE ### (≈ 2 lines of code) # Compute x_norm as the norm 2 of x. Use np.linalg.norm(..., ord = 2, axis = ..., keepdims = True) x_norm = np.linalg.norm(x, axis = 1, keepdims = True)
# Divide x by its norm. x = x / x_norm ### END CODE HERE ###
Exercise: Implement a softmax function using numpy. You can think of softmax as a normalizing function used when your algorithm needs to classify two or more classes. You will learn more about softmax in the second course of this specialization.
# GRADED FUNCTION: softmax
defsoftmax(x): """Calculates the softmax for each row of the input x. Your code should work for a row vector and also for matrices of shape (n, m). Argument: x -- A numpy matrix of shape (n,m) Returns: s -- A numpy matrix equal to the softmax of x, of shape (n,m) """
### START CODE HERE ### (≈ 3 lines of code) # Apply exp() element-wise to x. Use np.exp(...). x_exp = np.exp(x)
# Create a vector x_sum that sums each row of x_exp. Use np.sum(..., axis = 1, keepdims = True). x_sum = np.sum(x_exp, axis=1, keepdims=True)
# Compute softmax(x) by dividing x_exp by x_sum. It should automatically use numpy broadcasting. s = x_exp / x_sum
Exercise: Implement the numpy vectorized version of the L1 loss. You may find the function abs(x) (absolute value of x) useful.
# GRADED FUNCTION: L1
defL1(yhat, y): """ Arguments: yhat -- vector of size m (predicted labels) y -- vector of size m (true labels) Returns: loss -- the value of the L1 loss function defined above """
### START CODE HERE ### (≈ 1 line of code) loss = np.sum(abs(y - yhat)) ### END CODE HERE ###
Exercise: Implement the numpy vectorized version of the L2 loss. There are several way of implementing the L2 loss but you may find the function np.dot() useful. As a reminder, if $x = [x_1, x_2, …, x_n]$, then np.dot(x,x) = $\sum_{j=0}^n x_j^{2}$
# GRADED FUNCTION: L2
defL2(yhat, y): """ Arguments: yhat -- vector of size m (predicted labels) y -- vector of size m (true labels) Returns: loss -- the value of the L2 loss function defined above """
### START CODE HERE ### (≈ 1 line of code) loss = np.sum(np.dot(y - yhat, y - yhat)) ### END CODE HERE ###